Question

In triangle
ABC, AB = AC, D is a point inside the triangle such that angle DBC = angle DCB prove that triangle BADis congruent to triangle CAD​

Answer 1

Answer:

Since AB = AC ∠ABC = ∠ACB But ∠DBC = ∠DBC ⇒ ∠ABD = ∠ACD Now in ΔABD and ΔADC AB = AC AD = AD ∠ABD = ∠ACD Therefore, ΔABD ≅ ΔADC