Question

In triangle ABC, AB=AC From A,AD is dropped perpendicular to BC .Prove that BD=BC ​

Answer 1

Answer:

angle ADB=ADC=90

Therefore, In triangle ABD and ACD,

AB=AC

angle ABD=angle ACD

AD is common.

By SAS,

the triangles are congruent.

By CPCT,

BD=CD

Answer 2

Answer:

angle ADB=ADC=90

Therefore, In triangle ABD and ACD,

AB=AC

angle ABD=angle ACD

AD is common.

By SAS,

the triangles are congruent.

By CPCT,

BD=CD