Question

In triangle ABC, AB=AC.P,M and N are mid points of BC,AB and AC.prove that AMPN is a rhombus and AP is perpendicular on BC

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Given:- ABC is a △,M and N are the mid-points of AB and AC respectively. The altitude AP to BC intersect MN at O.

To prove:- AO=OP

Proof:-

Since M and N are the mid points of AB and BC,

By mid point Theorem,

MN∥BC

MN=

2

1

BC

Now In △ABP,

Since M is the mid point of AB,MO∥BP.

Therefore by Converse of midpoint theorem

O is the midpoint of AP

∴AO=OP

Hence proved.

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