Question

In triangle ABC, AB=AC. Prove that the bisector of angle BAC is also the perpendicular bisector of the base.​

Answer 1

Answer:

Step-by-step explanation:

To prove :

Angle a bac is 90°

ab=ac

So now we see that angle b and c are same and we also see that abc is an isosceles triangle.

B+c is obviously greater than a is obviously greater than a

So now we say that a + b + c equal to 180 degree

2b+a=180°

B+a =90°

Assuming that now as b and c are same and a is equal to 90°

And also b and c angles are now complimentary

So we have our answer...