In triangle ABC, AB=AC The bisector of AngleB & angleC intersects on side AC & side AB in the points D & E respectively then prove that seg ED || Seg BC.
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ad÷db=ae÷ec
it's an isosceles triangle.
in triangle BCA,cd ÷da=bc÷ba.
in triangle cab,ae ÷eb=ca ÷cb.
ab=ac and also take reciprocal.
so ad by db is equal to ae by EC.
by Converse of bpt,ed is parallel to BC.
it's an isosceles triangle.
in triangle BCA,cd ÷da=bc÷ba.
in triangle cab,ae ÷eb=ca ÷cb.
ab=ac and also take reciprocal.
so ad by db is equal to ae by EC.
by Converse of bpt,ed is parallel to BC.
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