In triangle ABC, AB = AC = x , BC = 10 cm and the area of the triangle is 60 cm square. Write down an equation in x and solve to find x
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Answered by
2
area of triangle = 1/2 base*height
60 = 1/2 *10*x
60= 5x
or , x= 60/5
so x= 12 cm^2 is your answer...
Answered by
2
Step-by-step explanation:
In ∆ ABC ,
two sides AB & AC ( x cm ) are equal .
So , it's a isosceles triangle .
Area of isosceles triangle = (b/4)* √4a²-b²
60 = (10/4) * √4x²-100
60 × 4/10 = √4x²-100
24 = √4x²-100
576 = 4x² - 100
4x² = 676
x² = 169
x = 13 cm
So , two equal sides of this isosceles triangle
are 13 cm .
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