Question

In triangle ABC,
AB= AC = x; BC = 10 cm and the area of triangle is 60 sq.cm. Find x​

Answer 1

Step-by-step explanation:

ANSWER

Given AB=AC=x

So ABC is an isosceles triangle.

AD⊥ BC

The altitude to the base of an isosceles triangle bisects the base.

BD=DC=10/2=5cm

Given area =60cm

2

1/2×base×height=1/2×10×AD=60

AD=60×2/10

AD=60/5

AD=12cm

ADC is a right triangle.

AC

2

=AD

2

+DC

2

x

2

=12

2

+52

x

2

=144+25

x

2

=169

Taking square root on both sides

x=13 cm

Hence the value of x is 13cm.

solution

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