Question

in triangle abc,AB+BC=10cm ,BC+CA=12cm,CA+CB =16cm then perimeter of triangle ABC is​

Answer 1

Answer:

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Step-by-step explanation:

It is given that

AB+BC=10 cm ....(i)

BC+CA=12 cm ....(ii)

CA+AB=16 cm ....(iii)

Adding (i), (ii) and (iii), we get

2(AB+BC+CA)=10+12+16

⇒2(AB+BC+CA)=38

⇒ AB+BC+CA=19 cm

Therefore, perimeter of △ABC is 19 cm.