Question

In triangle ABC, AB BC =AC, find < A. 41. The angles of a quadrilateral are in the ratio 3: 5 :9: 13. Find all the angles of the quadrilateral.​

Answer 1

Answer:

Let the angles of the quadrilateral be 3x, 5x, 9x and 13x.

∵ Sum of all the angles of quadrilateral = 360°

∴ 3x + 5x + 9x + 13x = 360°

⇒ 30x = 360°

∴ 3x = 3 × 12° = 36°

5x = 5 × 12°= 60°

9x = 9 × 12° = 108°

13x = 13 × 12° = 156°

⇒ The required angles of thequadrilateral are 36°, 60°, 108° and 156

Answer 2

Step-by-step explanation:

Let angles in the ratio 3:5:9:13

Be a,b,c & d

Let a =3x, b=5x,c=9x,d=13x

Let a=3x,b=5x,c=9x,d=13x

We know that

Sum of angeles of a quadrilateral is 360° ,

a+b+c+d=360°

3x+5x+9x+13x=360°

30x=360°

$x = \frac{360}{30}$

x=12°

Hence,the angles are

a=3x=3×12°=36°

b=5x=5×12°=60°

C=9x=9×12°=108°

d=13x=13×12°=156°