In triangle ABC , AB=BC and angle ACB =43° .Find angleABC and angle BAC.
Answers
Step-by-step explanation:
if AB=BC (angle opposite. to equal sides)
therefore Angle C=A
angle A=43
A+B+C=180
43+43+C=180
B=94
∠ABC = 94° and ∠BAC = 43°.
To find : ∠ABC and ∠BAC.
Given :
In ΔABC,
AB = BC
Here, AB = BC
Reason : When two sides of a triangles are equal then it is said to be an isosceles triangle.
Hence, ∠ACB = ∠BAC
In isosceles triangle, if two sides are equal then its opposite angles are equal
So, ∠BAC = 43° [ ∵ ∠ACB = 43° ]
In triangle, sum of the angle is 180°.
∠ACB + ∠BAC + ∠ABC = 180°
43° + 43° + ∠ABC = 180°
86° + ∠ABC = 180°
∠ABC = 180° - 86°
∠ABC = 94°
Therefore, the value of ∠ABC is 94° and ∠BAC is 43°.
To learn more...
1. In triangle ABC, AB=BC and angle B=64 degree Find angle C
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2. In a triangle ABC, AB=AC, D is a point on AB such that AD=DC=BC. Show that angle BAC = 36°
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