Question

In triangle ABC, AB=BC and angle B=64 degree Find angle C

Answer 1

Answer:

Step-by-step explanation:

B=64°

A+B+C=180°

Equal side is angle equal

A=C

C+B+C=180°

2C=180°-64°

2C=116°

C=58°

Answer 2

∠C = 58°

Step-by-step explanation:

Given,

In ΔABC,

AB=BC,∠B = 64°

⇒ ∠BAC = ∠BCA [Angle opposite to equal sides are always equal]

Now,

∠ABC +∠ACB +∠BAC =180° [Angle sum property of the triangle]

⇒∠ABC+∠ACB+∠ACB=180°

⇒∠ABC+2∠ACB=180°

⇒64+2∠ACB=180°

⇒2∠ACB = 180-64

⇒∠ACB =$\frac{180-64}{2}$

             = 58°

Hence,∠C = 58°