Question

In triangle ABC  AB= BC and D is the mid point of BC . Draw rough diagram and show that             ∆ABD≅∆ACD . Also show that AD bisect angle A     ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

(a) In triangle ABD and ACD,

AD=AD

AB=AC

BC=CD [D is mid-point at BC]

(b) By using part a of the solution, we get 

∴ △ABD≅△ACD  ... SSS criterion