In triangle ABC AB= BC and D is the mid point of BC . Draw rough diagram and show that ∆ABD≅∆ACD . Also show that AD bisect angle A
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therefore triangle ABD is congruent to ACD
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(a) In triangle ABD and ACD,
AD=AD
AB=AC
BC=CD [D is mid-point at BC]
(b) By using part a of the solution, we get
∴ △ABD≅△ACD ... SSS criterion
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