Question

in triangle ABC AB = BC , B = 3x + 10 , A = 2x - 20. calculate each angle of the triangle​

Answer 1

Answer:

In △ABC,

∵AB=BC

∴∠C=∠A=(2x−20)°(∵ angle oppsite to the equal sides are equal)

∠B=x°

As we know that sum of all interior angles of a triangle is 180°.

∴∠A+∠B+∠C=180°

⇒(2x−20)°+x°+(2x−20)°=180°

⇒(5x−40)°=180°

⇒5x=180°+40°

⇒x=

5

220

=44°

∴∠B=44°

Hence, the correct answer is 44.