In triangle ABC, AB= BC = CA and AD = BC=CA. Then
AD^2 is equal to
(a) 1/2DC^2
(b) DC
(c) 2DC^2
(d) 3DC^2
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Answer:
Answer
Correct option is
C
3CD
2
Given, equilateral triangle ABC, AD⊥BC
Since, it is an equilaateral triangle, the perpendicualr also bisects the side.
Hence, BD=DC or BD=
2
1
BC=
2
1
AB
Now, In △ABD, we have
AB
2
=AD
2
+BD
2
⇒AB
2
−BD
2
=AD
2
⇒BC
2
−BD
2
=AD
2
⇒(2CD)
2
−CD
2
=AD
2
⇒3CD
2
=AD
2
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