Question

In triangle ABC AB=c, BC=a,AC=b angle BAC is theta then area of triangle BAC is ?

Answer 1

ANGLE BAC KITNA H ISME

Answer 2

Area of $\triangle ABC$ is given $\sqrt{s(s-a)(s-b)(s-c)} cm^{2}$

Step-by-step explanation:

Given,

In $\triangle ABC$ where $AB=c,BC=a,AC=b$ and $\angle BAC=\theta$

∵ All sides are not equal of $\triangle ABC$ then it is scalene triangle.

Area of $\triangle ABC$ is given by Heron's Formula,

Area of $\triangle ABC=\sqrt{s(s-a)(s-b)(s-c)}$ $cm^{2}$

Where $s$ is given by,

$s=\frac{a+b+c}{2}$

∴ Area of $\triangle ABC$ is given $\sqrt{s(s-a)(s-b)(s-c)} cm^{2}$