In triangle ABC, AB is equal to AC ,
BE perpendicular to AC
and CF is perpendicular to AB.
Prove that:
1. BE=CF
2. AF=AE
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1.to prove BE = CF
given : angle 1=angle 2= 90°
angle 3=angle 4 ( base angles)
in triangle BFC & triangle CEB
angle1=2
angle 3=4
BC=BC (common )
by AAS
BE =CF (cpct)
2. to prove AE =AF
AB = AC given
FB = BC (cpct)
AF +FB=AE +BC
FB and BC are cancelled
therefore AF= AE
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