in triangle ABC AB is equal to AC is equal to 15 cm and BC is equals to 18 cm find cos angle abc
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Answer:
3/5
Step-by-step explanation:
Here ABC is a triangle in which AB = 15 cm , Ac = 15 cm and BC = 18 cm
Draw AD perpendicular to BC ,D is mid - point of BC .
Then ,BD = DC = 9 cm
In right angled triangle ADB
By Pythagoras theorem , we get
AD = 12 cm
cos angle ABC = Base / Hypotenuse
In right angled∆ ABD , Angle ABC = Angle ABD
= BD / AB
= 9/15
= 3/15
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