In triangle ABC AB is equal to AC is equal to X BC is equal to 10 centimetre and the area of the triangle is 60 CM square find X
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5
x= 12 cm
AB = AC= 12 cm
AB = AC= 12 cm
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16
given that two sides of triangle is equal and equals to x .
then h of triangle = √(X²-(10\2)²)=√x²-25
now area of triangle = 1\2 ×h ×b =60
or 1\2×10×√x²-25 =60
or 5 √x²-25 =60
or √x²-25 = 12
squaring both sides we get
x²-25=144
or x²=169
or x =13 ans.
then h of triangle = √(X²-(10\2)²)=√x²-25
now area of triangle = 1\2 ×h ×b =60
or 1\2×10×√x²-25 =60
or 5 √x²-25 =60
or √x²-25 = 12
squaring both sides we get
x²-25=144
or x²=169
or x =13 ans.
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