Question

In triangle ABC, AB is equal to AC prove that the bisector of BAC is also the perpendicular bisector of the base.
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Answer 1

in ∆abd and ∆acd

ab=ac(given)

ad=ad(common)

angle bad= angle cad ( given bisector of bac)

so (SAS CONGRUENCY RULE )

∆ABD is congruent to ∆cad

so bd=cd (C.P.C.T.)

angle cda= angle cda (C.P.C.T)

HOPE IT HELPS

Answer 2

Answer:

given,

AB=AC

LET AD be the angle bisector of angle BAC.

to prove :BD=CD

proof:----

in ∆ABD and ∆ADC,

AB=AC(given)

angleBAD= angle DAC(given)

AD=AD(common)

:.from SAS criteria,

∆ABD congruent ∆ADC.

:.BD=DC(CPCT).

hence proved...

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