In triangle ABC,AB=P, DB=P-2, AE=P+2, EC=P-1 THEN FIND THE VALUE OF P?
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if DE parallel BC then the problem can be solved . which here not mentioned.Taking such,
then AB/DB=AC/EC,
or p/(p-2)=(p+2+p-1)/(p-1)
solving we have p=√3+1.
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