Math, asked by malanaik20794, 7 months ago

In triangle ABC,AB=P, DB=P-2, AE=P+2, EC=P-1 THEN FIND THE VALUE OF P?​

Answers

Answered by Subhaschandrahaldar1
3

Answer:

if DE parallel BC then the problem can be solved . which here not mentioned.Taking such,

then AB/DB=AC/EC,

or p/(p-2)=(p+2+p-1)/(p-1)

solving we have p=√3+1.

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