Question

In triangle abc,AB perpendicularBC,BD perpendicular to ACCE bisects Angle C where E is point on BD.If Angle A is 30,then Angle CED​

Answer 1

Answer:

In ΔABC,

∠ABC+∠BAC+∠ACB=180

∘

⇒90

∘

+30

∘

+∠ACB=180

∘

⇒∠ACB=180

∘

−120

∘

=60

∘

Now CE bisects ∠C⇒∠ECD=30

∘

Also, BD⊥AC⇒∠EDC=90

∘

∴ In ΔDEC,

∠ECD+∠CED=180

∘

⇒30

∘

+90

∘

+∠CED=180

∘

⇒∠CED=180

∘

=180

∘

−120

∘

=60

∘

.

Answer 2

Step-by-step explanation:

see this is same type of sum

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