In triangle ABC, ∠ABC = 53°. Find the sum of ∠ACB and ∠BAC.
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Answered by
1
the sum of ACB Angle and BAC Angle will be 180°-53°=127°
sarahrihabtg:
thank u
Answered by
3
As the sum of all angles of a triangle is 180°.
so,
∆abc+ ∆acb+∆bac= 180°
53°+∆acb+∆bac=180°
∆acb+∆bac=180°-53°=127°
so,
∆abc+ ∆acb+∆bac= 180°
53°+∆acb+∆bac=180°
∆acb+∆bac=180°-53°=127°
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