In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. BC=9 and HC=3, find AH.
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Answer:
Step-by-step explanation:
BH is altitude means it's a perpendicular height from point B to side AC.
Now we hv two triangles ABH and BCH
In trBCH using Pythagoras
BH= √54 cm
In trABC Pythagoras
AB^2=AC^2-81 Eq-1
Put AC=AH+3
In trABH using Pythagoras
AB^2=BH^2+AH^2. Eq2
BH^2=54
Using Eq1 and Eq2
AH=7.5 cm
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