Question

in triangle ABC, ABC = 90°
Seg BD perpendicular seg AC [A-D-C]
BD 12. AD-8
Find : 1) DC.II) A(AABC), III) BC
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Answer 1

Answer:

Given:

∠BDC=90∘

∠ABC=90∘

Let ∠BCD=x∘

Using triangle sum property in △BDC, ∠DBC=90−x∘

Also ∠ABD=x∘

Using triangle sum property in △ADB, ∠BAD=90−x∘

Now considering △BDC and △ADB

∠BDC=∠BDA              [∵∠BDC=∠BDA=90∘]

∠DBC=∠DAB              [∵∠DBC=∠DAB=(90−x)∘]

So by AA

△BDC∼△ADB

Hence CDBD=BDAD

CD8=84

CD=16

Hence CD=16cm

Step-by-step explanation:

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