In triangle ABC AC=2√10 if tan B =2 and tanC=3 find the length of the sides BC and AB
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Given:-
AC length=2√10
tanb=2
tanc=3
ATQ,
tanc=>p/b=AB/BC=3
AB/BC=3
AB=3BC
By pythogorous theorm:-
AB²+BC²=AC²
=>(3BC)²+BC²=AC²
=>9BC²+BC²=AC²
=>10BC²=>AC²
=>BC²/AC²=1/10
=>AC²/BC²=10
=>AC/BC=√10
=>2√10/BC=√10 {putting the value of AC}
=>BC=2
So,AB=6 {put the value
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AB = 6 units
BC = 2 units
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