Question

In triangle ABC, AC = 3AB. If AD bisects angle A with D lying on BC and E is the foot of the
perpendicular from C to AD, then (area of ΔABD)/(area of ΔCDE)
is equal to-
a) 2
b) 1/3
c) 1/4
d) 2/3
please solve​

Answer 1

Step-by-step explanation:

I think answer is 2/3 not confirm