Question

IN TRIANGLE ABC ;
AC=BC=5 CM ;
AB=6 CM ;
ANGLE B= 50 DEGREE ;
ANGLE A = 2x + 20 DEGREE ;
FIND ANGLE BAC


PLZ SOLVE THIS OF 9TH STANDARD

Answer 1

Answer:

50 degrees

Step-by-step explanation:

Since AC = BC

Angle(A) = Angle(B) (Angles opposite equal sides are = in an isos. triangle)

50 = 2x + 20

30 = 2x

x = 30/2

x = 15 degree

so Angle(BAC) = 2 x 15 + 20

= 30 + 20

= 50 degree

Answer 2

Given: In triangle ABC ;

AC=BC=5 CM ;

AB=6 CM; angle B= degree; angle A = 2x + 20

To find: We have to find an angle BAC.

Solution:

In a triangle ABC, AC=BC=5 CM so it is an isosceles triangle.

In an isosceles triangle, the equal opposite sides have equal angles.

Thus the angles opposite to AC and BC that is the angle ABC and BAC are equal.

So, we can write-

ABC=BAC

50=2x+20

2x=30

x=15.

Thus the value of x is 15.

The BAC is equal to 2×15+20=50

So, angle BAC=50 degree.