in triangle abc
AC = BC
angle BAC is bisected by AD
AD = AB
find angle ACB
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Step-by-step explanation:
In △ABC,
AC=BC
=>∠BAC=∠ABC=x(say)
In △ABD,
AB=AD
=>∠ABD=∠ADB=y(say)
But ∠ABD=∠ABC
=>x=y
Also ∠BAD=180°−2x(in△ABD,sum of∠BAD,∠ABD,∠ADBis180°)
But AD bisects ∠BAC into ∠BAD and ∠DAC
∴∠BAD=∠DAC=
2
x
=>180°−2x=
2
x
=>180°=
2
5x
=>x=72°
∴∠ACB=180°−144°=36°
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आंसर इक्वल टू 45 डिग्री
पहले हमको ट्रायंगल एबीडी अंधे इक्वल टू 45 डिग्री एंगल बी इक्वल टू 90 डिग्री एंड एंगल ए इक्वल टू 14 डिग्री टोटल अंजलि कॉल टू सो angle C 45 डिग्री
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