Math, asked by amartyrai2020, 3 days ago

in triangle abc
AC = BC
angle BAC is bisected by AD
AD = AB
find angle ACB

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Answers

Answered by rudraa30
3

Step-by-step explanation:

In △ABC,

AC=BC

=>∠BAC=∠ABC=x(say)

In △ABD,

AB=AD

=>∠ABD=∠ADB=y(say)

But ∠ABD=∠ABC

=>x=y

Also ∠BAD=180°−2x(in△ABD,sum of∠BAD,∠ABD,∠ADBis180°)

But AD bisects ∠BAC into ∠BAD and ∠DAC

∴∠BAD=∠DAC=

2

x

=>180°−2x=

2

x

=>180°=

2

5x

=>x=72°

∴∠ACB=180°−144°=36°

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Answered by girisumanta1
1

आंसर इक्वल टू 45 डिग्री

पहले हमको ट्रायंगल एबीडी अंधे इक्वल टू 45 डिग्री एंगल बी इक्वल टू 90 डिग्री एंड एंगल ए इक्वल टू 14 डिग्री टोटल अंजलि कॉल टू सो angle C 45 डिग्री

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