Question

In triangle ABC,AC is grater than AB and AD is the bisector of angle A.show that angle ADC is greater than angle ABD

Answer 1

is the angle ADB or ABD?

Answer 2

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$<b><u>Answer</u></b>$

$<b>To show: ∠ADC > ∠ABD</b>$

$<b><u>Step-by-step explanation</u></b>$


Given that:

AD id the bisector of ∠A of △ABC.

Hence, ∠DAB = ∠DAC

∠BDA is the exterior angle od △DAC.

Hence, ∠BDA > ∠DAC

(OR)


∠DAC = ∠DAB


Since, ∠DAC = ∠DAB

AB > BD

$<b>In a triangle, side opposite to greater side is greater.</b>$

Therefore, hence showed.

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