Question

In triangle ABC, AC is perpendicular to BC and E is a point on AC produced. ED is perpendicular to AB is drawn to meet BC at O. Prove that angle CEO =Angle DBO​

Answer 1

Answer:

If BC=12cm, AD=3cm and DC =2cm, then prove that triangle ... to triangle ADE and hence find the lengths of AE and DE. 2 ... AC^2 + BC^2= AB^2 ... 5/AE= 13/3= 12/ED