Question

In triangle ABC acosA+bsinB+ccosC=

Answer 1

Area of the triangle=1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]

[taking (x1,y1)=(-1,0),(x2,y2)=(2,-4) and (x3,y3)=(2,3)]

Area=1/2[-1(-4–3)+2(3–0)+2(0+4)]

Area =1/2[7+6+8]=21/2=10.5 sq units