Question

In triangle ABC, AD=AC. Show that AB is greater thanAD

Answer 1

here is your answer...

the figure is like I have made above...if u are confused whether it is right or not then here is the clarification...ad and ac must be opposite to a common perpendicular otherwise their equality will fail the Pythagoras theorem...

so from the constructional point of proof, if ad intersects BC then d will lie somewhat between b and c... so taking as as the common perpendicular we can observe that BE will always be greater than ED...
also from the Pythagoras theorem...
we can see that AB is always greater than AD