in triangle ABC, AD and CE are perpendicular from A and C on the opposite sides. If AD =8.6cm,BC=14cm, AB =10 cm, find CE.
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We know that AD= AF
BD=BE
CE=CF
Let AD= AF=x
BD=BE=y
CE=CF=z
Then x+y=12
y+z=8
x+z=10
On Solving above equation we get x=7,y=5,z=3
So AD=7 , BE=5 , CF= 3
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