Question

in triangle abc AD | BC and AD bisects angle A. prove that triangle ABD=~ACD .
also prove that triangle ABC is isosceles.​

Answer 1

Step-by-step explanation:

Consider Δ ADB and Δ ADC.

BD = CD as AD bisects BC.

∠BAD = ∠CAD because AD bisects ∠A

∠ADB = ∠ADC = 90° because AD is perpendicular to BC

Hence, by ASA (Angle, side, angle) property, ABD≅ACD

Now, because ΔADB≅ΔADC, AB equals to AC, hence ΔABC is isosceles.

Answer 2

Answer:

Hey Mate here is your answer

Step-by-step explanation:

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