Math, asked by aadityakapare, 1 month ago

In triangle ABC, AD ⊥ BC. If tan B= 3/4, and tan C= 1/3 and BC= 65 cm, calculate the length of AD.
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Answered by saran00766
1

Answer:

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Answered by SharannyaPawar
0

Answer:

15cm

Step-by-step explanation:

tan B = \frac{AD}{BD}=\frac{3}{4}

Let AD =3x & BD =4x

Therefore DC=65-4x

tan C = \frac{AD}{DC } == > \frac{1}{3}  =\frac{3x}{65-4x}

65-4x+9x  ==> 65 = 13X ++> x = 5

Therefore AD + 3x + 15cm

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