Question

In triangle ABC, AD bisect angle A meets side BC at D and measure of angle B is 55 degree and angle C is 45 degree then find angle ADB.

What is answer plzzzzzzz ​

Answer 1

Step-by-step explanation:

yes it is very easy

first you find angleA by angle sum property of triangle then a comes 80 degree in question it is given that ad bisect angle A then angle bad =40 and angle cad=40 then in triangle abd angle b=55 and angle a=40 the by angle dum property u find angle d which comes 85 degree.

plz mark me as brainlist.

Answer 2

Given

⭐∠1 = ∠2 ( AD bisects ∠A)

⭐∠B = 55⁰

⭐∠C = 45⁰

To find

⭐∆ADB

solution

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➣ In ∆ABC

⟶ ∠A + ∠B + ∠C = 180⁰

⟶ ∠1 + ∠2 + 55⁰ + 45⁰ = 180⁰

⟶ ∠1 + ∠1 = 180⁰ - 100⁰

⟶ 2∠1 = 80⁰

⟶ ∠1 = $</p><p>\small{\underline{\tt{\purple{40⁰}}}}$

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★$\boxed{∠1 = ∠2 = 40⁰ }$

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➣ In ∆ ADB

⟶ ∠1 + 55⁰ + ∠ADB = 180⁰

⟶ 95⁰ + ∠ADB = 180⁰

⟶ ∠ADB = $\small{\underline{\tt{\green{85⁰}}}}$

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Hope it helps