Question

in triangle abc, ad bisects angle a, angle abc = 75 and angle acb = 35
arrange sides ab, bd and dc in ascending order of their lengths.

Answer 1

Step-by-step explanation:

We know that the side opposite to the greatest angle is larger side.

ABC= 75°

ACB = 35

BAC= 180-(75+35)

BAC= 70

So, AC > BC > AB

DAC = DAB= 35

ADB= 70

ADC= 110

So, AD > AB > BD

So, AC > AD = CD

So, BD < AB < CD

Answer 2

Answer:

Step-by-step explanation:

∠A + ∠B + ∠C = 180  {Angle sum property of triangle}

∠A + 75 + 35 = 180

∠A + 110 = 180

∠A = 180- 110 = 70

AD bisects ∠A.

∠BAD = ∠CAD = 70/2 = 35°

Opposite angle of side AB =∠C

Opposite angle of side BD = ∠BAD

Opposite angle of side DC = ∠CAD

Ascending order of angles: ∠BAD & ∠BAD  , ∠C

Ascending order of side: BD & CD , AB