Question

In triangle ABC, AD bisects Angle BAC AND AB=AC. PROVE THAT ANGLE ADB IS EQUAL TO ANGLE BDC=90 DEGREE

Answer 1

Answer:

this Will help full for u

Answer 2

Answer:

MARK AS A BRAINLIST

MARK AS A BRAINLIST

MARK AS A BRAINLIST

Step-by-step explanation:

Method 1:

When AD is the angle bisector of <BAC

ABC is an isosceles triangle in which AB = AC and AD is the bisector of <BAC.

In triangles ABD and ACD

<B = <C

AB = AC

AD is common.

Therefore triangles ABD and ACD are congruent, and so

<ADB = <ADC = 90 degrees because BCD is a straight line and = 180 degrees.

QED.

Method 2:

When AD is the bisector of BC

ABC is an isosceles triangle in which AB = AC and AD is the bisector of BC.

In triangles ABD and ACD

<B = <C

AB = AC

BD = CD.

Therefore triangles ABD and ACD are congruent, and so

<ADB = <ADC = 90 degrees because BCD is a straight line and = 180 degrees.

QED.