Question

in triangle abc ad bisects angle bac and ad = dc if angle bda is 70degree find angle acd aand abd​

Answer 1

Answer:

ad= dc

angle bda =70°

Now,

angle bda + angle adc = 180°

angle adc = 180° - 70°

angle adc = 110°

angle adc + angle dca + angle dac = 180°

angle dac = angle dca

2 angle dca = 180 - 110

angle dca = 35°

angle bad = angle cad

angle bad = 35°

angle adb + angle dab + angle abd = 180°

angle abd = 180 - 105

angle abd = 75

hence

angle abd = 75°

angle acd = 35°

may be it help you ✌️✌️✌️✌️✌️

Answer 2

Answer:

angle abd = 75°

angle acd= 35°