Question

in triangle ABC, AD bisects angle BAC and AD=DC. If angle BDA=70degree, Then calculate angle ACD and angle ABD. Please answer fast. I will mark him brainlist .

Answer 1

given: AD=DC Hence angle dac-angle dca =x(say) we know that the exterior angle is equal to sum of its opposite interior angle hence, angle ADB=angle (dac+dca) 70=x+ x x=35 and angle bad=angle dac = 35° Now, in triangle ABD we have 70°+35°+angle ABD=180° angle ABD=180°-105°=75°