Question

In triangle ABC, AD bisects angleA and angleC greater angle A.prove angle ADB is greater than the angle ADC.

Answer 1

Answer:

Step-by-step explanation:

AD bisects angle A thus Angle BAD=Angle CAD

In triangle ADB

Angle B+ Angle ADB+Angle BAD=180°

Angle ADB=180°-Angle B-Angle BAD

In triangle ADC

Angle C+Angle ADC+ Angle CAD=180°

Angle CAD=180°-Angle CAD-Angle C

We know that CAD= BAD

Angle ADC=180°-Angle BAD- Angle C

We know that Angle C>Angle B, thus in while calculating the value of Angle ADC we are subtracting a larger amount compared to what we subtract to calculate Angle ADB, thus

Angle ADB>Angle ADC