In triangle ABC,AD is angular bisector of angle A and angle B is twice of angle C and AB=DC Prove that angle A=72°
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rakhithakur
Secondary SchoolMath 5+3 pts
ABC is a triangle in which Angle B is equals to 2 angle C .D is a point on BC such that AD bisects angle BAC and ab is equal to CD prove that angle BAC is equal to 72 degree
Report by Sfgjgs 15.09.2018
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bhambhambhole
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bhambhambhole
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Shaizakincsem
Shaizakincsem Samaritan
Thank you for asking this question, here is the answer:
Triangle ABC and ADC are similar (two sides and one angle is equal)
So ∠ CAD = ∠ ACB = C
∠BAC = 2c
And in triangle ABC ∠BAC + ∠ABC + ∠ACB
= 2c+2c+c
= 5c
= 180c
= 180/5
= 36
∠BAC = 2c
= 2x36
72
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