in triangle abc ad is median BL and CM of perpendicular drawn from B and C respectively on the and produced prove that b l is equal to cm
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In ΔBDL and ΔCDM,
∠BLD=∠CMD(both equal to 90°)
∠BDL=∠CDM(vetically opposite angles are equal
BD=CD(AD is median)
∴ΔBDL≡ΔCDM(AAS conguency)
⇒BL=CM(cpct,corresponding parts of congruent triangles)
Hence Proved
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