In triangle ABC,AD is median.show that AB+BC+AC >2AD.
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Answer:
BD=CD
Angle ABD = Angle ACD
We know that,
Sum of 2 sides of a triangle is always greater than the third side.
So,
1. AB+BD > AD
2. AC+CD > AC
3. AB+BD+CA+CD > 2AD
SO, AB+BC+CA > 2AD
Hence, Proved.
Hope this helps:)
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