In triangle ABC , AD is perpendicular to BC , angle c =45° . BD =5 . AD=8 root 2 . find AD and BC.
please solve by 90°-45°-45° theorem
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Answer:
triangle ADC is isoceles,
given angle ACD=45°, angle ADC=90°
Therefore angle CAD=45° (by angle sum property of triangle)
hence AD=DC
given AD=8√2 and BD=5
so, CD=8√2
therefore BC=5+8√2=16.312
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