In triangle ABC AD is perpendicular to BC ,BD:CD=3:1 than prove 2(AB2-AC2)=BC2
NemaRamNetar:
tell ans. plz
Answers
Answered by
43
2(AB2-AC2)=BC2
2(AB2-AC2)
=2(AD2+BD2-AD2-DC2)
=2{(BD+DC)(BD-DC)}
=2{BC(3CD-DC)
=2(BC)(2CD)
=(BC)(4CD)
=(BC)(3CD+CD)=BC2
2(AB2-AC2)
=2(AD2+BD2-AD2-DC2)
=2{(BD+DC)(BD-DC)}
=2{BC(3CD-DC)
=2(BC)(2CD)
=(BC)(4CD)
=(BC)(3CD+CD)=BC2
Answered by
18
hope this will help you
Attachments:
Similar questions