in triangle abc ad is perpendicular to bc given that bd is greater than cd, proof that ab is greater than ac
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Answer:
Okay so here is your answer
U need to apply Pythagoras theorem
Take 2 triangles - triangle ABD (angle D is 90) ; n triangle ACD(angle D is 90)
So u will get :
In triangle ABD,
AB^2= AD^2+BD^2
AD^2=AB^2-BD^2 -----equation 1
In triangle ACD,
AC^2=AD^2+CD^2
AD^2=AC^2-CD^2 -------equation 2
From equations 1 n 2 we get that
AB^2-BD^2=AC^2-CD^2
But BD is greater than CD n so it can b understood that AB is greater than AC coz "AB-something greater is equal to AC - something smaller"
I hope u r satisfied with the answer
arjun7774:
hiii
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