In triangle ABC , AD is the bisector of angle A.
AB = 12 cm , AC = 10 cm
What is BD:DC ?
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In any triangle, the bisector of an angle divides the opposite side in the ratio of the sides of the angle,
here ratio of sides of triangles are 12:10=6:5
here opposite side is divided in this ratio,
given that DB=6cm, so DC= 5cm(from 6:5)
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GIVEN : AD bisects ∠ A and
AB = 12 cm, AC = 20 cm, and BD = 5 cm.
Since AD is the bisector of ∠ A
then, AB/AC = BD/DC
[The internal bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle]
12/20 = 5/DC
12 x DC = 20 x 5
DC = 100/12
DC = 8.33 cm
Hence,CD = 8.33 cm.
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