Question

In triangle ABC, Ad is the internal bisector of angle a, ab=xcm,ac=5cm, bd=4.2cm and cd=3.5cm find the value of x?

Answer 1

Answer:

By Pythagoras theorem

AD² + CD² = AC²

AD ² + (3.5)² = 5 ²

AD = √25 - 12.25

AD = √12.75

AD = 3.58

Now area of ∆ = ½*b*h

= ½*7.7*3.58

= 27.566 (approx)

Answer 2

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